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| type = Component | | type = Component | ||
| prerequisite1 = Saving Bytes | | prerequisite1 = Saving Bytes | ||
| | | unlocks-level1 = 3 Bit Decoder | ||
| | | unlocks-level2 = Little Box | ||
| | | unlocks-component1 = 1 Bit decoder | ||
| scored = Yes | |||
| highscore = 3 | |||
| highscore-gate = 1 | |||
| highscore-delay = 2 | |||
| api-enum-id = decoder1 | |||
| api-enum-number = 24 | |||
}} | }} | ||
This level asks you to make a circuit that outputs On to one of two pins depending on the input signal. | This level asks you to make a circuit that outputs On to one of two pins depending on the input signal. | ||
Latest revision as of 21:14, 17 November 2023
| Section | Arithmetic |
|---|---|
| Type | Component |
| Prerequisite | Saving Bytes |
| Unlocks | 3 Bit Decoder Little Box |
| 1 Bit decoder | |
| Scored | Yes |
| High score | 3 |
| API | decoder1 (24) |
This level asks you to make a circuit that outputs On to one of two pins depending on the input signal.
Solution[edit | edit source]
As the truth table reveals, one output is the inverse of the input and the other is a copy of the input. So add a Not Gate for the first output and wire things up.
Spoiler
